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The INBREED Procedure |
The OUTCOV= data set has the following variables:
The functions of the variables _Panel_ and _Col_ can best be demonstrated by an example. Assume that there are three individuals in the first BY group and that, in the current BY group (Byvar=2), there are five individuals with the following covariance matrix.
COV | 1 | 2 | 3 | 4 | 5 |
1 | Cov(1,1) | Cov(1,2) | Cov(1,3) | Cov(1,4) | Cov(1,5) |
2 | Cov(2,1) | Cov(2,2) | Cov(2,3) | Cov(2,4) | Cov(2,5) |
3 | Cov(3,1) | Cov(3,2) | Cov(3,3) | Cov(3,4) | Cov(3,5) |
4 | Cov(4,1) | Cov(4,2) | Cov(4,3) | Cov(4,4) | Cov(4,5) |
5 | Cov(5,1) | Cov(5,2) | Cov(5,3) | Cov(5,4) | Cov(5,5) |
Panel 1 | Panel 2 |
Then the OUTCOV= data set appears as follows.
Byvar | _Panel_ | _Col_ | Individual | Parent | Parent2 | Col1 | Col2 | Col3 |
2 | 1 | COL1 | 1 | Cov(1,1) | Cov(1,2) | Cov(1,3) | ||
2 | 1 | COL2 | 2 | Cov(2,1) | Cov(2,2) | Cov(2,3) | ||
2 | 1 | COL3 | 3 | Cov(3,1) | Cov(3,2) | Cov(3,3) | ||
2 | 1 | 4 | Cov(4,1) | Cov(4,2) | Cov(4,3) | |||
2 | 1 | 5 | Cov(5,1) | Cov(5,2) | Cov(5,3) | |||
2 | 2 | 1 | Cov(1,4) | Cov(1,5) | . | |||
2 | 2 | 2 | Cov(2,4) | Cov(2,5) | . | |||
2 | 2 | 3 | Cov(3,4) | Cov(3,5) | . | |||
2 | 2 | COL1 | 4 | Cov(4,4) | Cov(4,5) | . | ||
2 | 2 | COL2 | 5 | Cov(5,4) | Cov(5,5) | . |
Notice that the first three columns go to the first panel (_Panel_=1), and the remaining two go to the second panel (_Panel_=2). Therefore, in the first panel, `COL1', `COL2', and `COL3' correspond to individuals 1, 2, and 3, respectively, while in the second panel, `COL1' and `COL2' correspond to individuals 4 and 5, respectively.
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