STAT 330: 98-1
Assignment 2 Solutions
I did not talk about this in class so all you could really do is look for obvious outliers or asymmetry. I see no sign of any problem.
where . Thus z = 1.65, P=0.10 and the test rejects at the 20% level but not at the 5% level. In part a) the type of error you might be making is type II, incorrectly accepting the null (because you do accept the null in a).
which leads to a P-value of 9.18% which I would describe as some, weak, evidence against the null hypothesis and in favour of the assertion that .
Now solve to get and similarly for a.
I remark that this model assumes that the buses always run exactly minutes apart and the writer arrives at a ``random time'' -- not very realistic.