Example 50.2: A Hierarchical Design
In this example, three plants are nested within
four pots, which are nested within three houses.
The FACTORS statement requests a random permutation of the numbers
1, 2, and 3 to choose Houses randomly.
The second step requests a random permutation of
the numbers 1, 2, 3, and 4 for each of those first three numbers
to randomly assign Pots to Houses.
Finally, the FACTORS statement requests a random
permutation of 1, 2, and 3 for each of the twelve
integers in the second set of permutations.
This last step randomly assigns Plants to Pots.
The following statements produce Output 50.2.1:
title 'Hierarchical Design';
proc plan seed=17431;
factors Houses=3 Pots=4 Plants=3 / noprint;
output out=nested;
run;
proc print data=nested;
run;
Output 50.2.1: A Hierarchical Design
|
| Obs |
Houses |
Pots |
Plants |
| 1 |
1 |
3 |
2 |
| 2 |
1 |
3 |
3 |
| 3 |
1 |
3 |
1 |
| 4 |
1 |
1 |
3 |
| 5 |
1 |
1 |
1 |
| 6 |
1 |
1 |
2 |
| 7 |
1 |
2 |
2 |
| 8 |
1 |
2 |
3 |
| 9 |
1 |
2 |
1 |
| 10 |
1 |
4 |
3 |
| 11 |
1 |
4 |
2 |
| 12 |
1 |
4 |
1 |
| 13 |
2 |
4 |
1 |
| 14 |
2 |
4 |
3 |
| 15 |
2 |
4 |
2 |
| 16 |
2 |
2 |
2 |
| 17 |
2 |
2 |
1 |
| 18 |
2 |
2 |
3 |
| 19 |
2 |
3 |
2 |
| 20 |
2 |
3 |
3 |
| 21 |
2 |
3 |
1 |
| 22 |
2 |
1 |
2 |
| 23 |
2 |
1 |
3 |
| 24 |
2 |
1 |
1 |
| 25 |
3 |
4 |
1 |
| 26 |
3 |
4 |
3 |
| 27 |
3 |
4 |
2 |
| 28 |
3 |
1 |
3 |
| 29 |
3 |
1 |
2 |
| 30 |
3 |
1 |
1 |
| 31 |
3 |
2 |
1 |
| 32 |
3 |
2 |
2 |
| 33 |
3 |
2 |
3 |
| 34 |
3 |
3 |
3 |
| 35 |
3 |
3 |
2 |
| 36 |
3 |
3 |
1 |
|
Copyright © 1999 by SAS Institute Inc., Cary, NC, USA. All rights reserved.
